2x + 5 - 5 = 9 - 5 2x = 4 x = 2
4x + 3 - 3 = -17 - 3 4x = -20 x = -5
2.5x - 3.2 + 3.2 = 9.3 + 3.2 2.5x = 12.5 x = 5
(y + 4)(y - 2) = 0 y + 4 = 0 or y - 2 = 0 y = -4, 2
t + 3 = (t - 3)2 = t2 - 6t + 9 0 = t2 - 7t + 6 0 = (t - 1)(t - 6) t = 1, 6 are possible solutions. Check, t = 1, (4)1/2 ≠ -2 --> is extraneous t = 6, (9)1/2 = 3 --> is a solution
_____ _
x = ±√ -48 = ±4√3i
x2 + 10x + 25 = 20 complete square of lhs
(x + 5)2 = 20 factor
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x + 5 = ±2√5
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x = -5 ± 2√5
x2 + 14x + 49 = 51 complete square of lhs
(x + 7)2 = 51 factor
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x + 7 = ±√51
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x = -7 ± √51
__________ _______
-6 ± √62 - 4×3×7 -6 ± √36 - 84
x = —————————————————— = —————————————— =
2×3 6
_____ _ _
-6 ± √ -48 -6 ± 4√3i -3 ± 2√3i
x = ————————————— = ——————————— = ———————————
6 6 3
________ _____
-3 ± √32 - 4×6 -3 ± √ -15
x = ———————————————— = ————————————— =
2 2
__
-3 ± √15i
x = ————————————
2
_______ _____
4 ± √16 - 52 4 ± √ -36 4 ± 6i
x = —————————————— = ———————————— = ———————— =
2 2 2
x = 2 ± 3i
2x + 3 + 6x - 4 = 8x - 2 + 1 8x - 1 = 8x - 1 This equation is an identity; it is true for all values of the variable x.
9x - 6 = 10x - 2 - x + 2 9x - 6 = 9x -6 = 0 This equation has no solution; it is not true for any value of the variable x.
6 = 2(x + 2) - 3x 6 = 2x + 4 - 3x = -x + 4 x = -2 This equation has no solution; if x = -2, the equation has undefined terms.
x2 + 3x + 2 = (x + 2) + 2(x + 1)
x2 + 3x + 2 = 3x + 4
x2 = 2
_
x = ±√2
Let x2 = u, then substitute:
u2 - 7u - 8 = 0
(u + 1)(u - 8) = 0
u = -1 or u = 8
Then,
x2 = -1 or x2 = 8
So the four solutions are:
_
x = ±i or x = ±2√2
Let x1/3 = u, then substitute: u2 - 5u + 6 = 0 (u - 2)(u - 3) = 0 u = 2 or u = 3 Then, x1/3 = 2 or x1/3 = 3 x = 8 or x = 27
x = x + 3 - 2(x + 3)1/2 + 1 2(x + 3)1/2 = 4 (x + 3)1/2 = 2 x + 3 = 4 x = 1
1 1 1 1
——— = ——— + ——— + ———
x a b c
abc = bcx + acx + abx = x(ac + ab + bc)
abc
x = ——————————————
ac + ab + bc
x3 - 23 = (x - 2)(x2 + 2x + 4)
x = 2 or
________ _____ _
-2 ± √ 4 - 16 -2 ± √ -12 -2 ± 2√3i
x = ———————————————— = ————————————— = —————————————
2 2 2
_
= -1 ± √3i
_
There are three solutions: x = 2, -1 ± √3i