(2005-09-29)
Dispersion Relation
The celerity of a wave as a function of its frequency.
In a given propagation medium, the dispersion relation,
is whatever gives the celerity of a wave in terms
of either its frequency (n )
or its wavelength (l).
The simplest dispersion relation is that of a nondispersive medium, for which the
celerity (u) is constant. For example, the celerity of
electromagnetic waves in a vacuum is
equal to Einstein's constant (u = c).
One common way to specify the dispersion relation is by giving
the pulsatance w = 2pn
as a function of the wave number
k = 2p/l
w = w(k)
(2005-09-29)
Group Speed
The speed at which a wave may carry information.
A wave where a single frequency is present is unable to carry any information.
v =
dw / dk
=
-l2
dn / dl
(2008-01-24)
Rayleigh scattering
(Tyndall effect, 1859)
(2007-07-24)
What makes the sky blue and sunsets red?
(2007-07-13)
Why do we perceive the Sun as yellow?
In 1859, John Tyndall (1820-1893)
observed that small particles suspended in a fluid scatter bluish light
(short wavelength) more strongly than reddish light (long wavelength).
This scattering of light by tiny particles is known either as the
Tyndall effect
or (more commonly) Rayleigh scattering.
The intensity of the effect varies inversely as the
fourth power of the wavelength involved.
One crude way to explain the main part of effect is to consider that
an incoming electromagnetic wave produces induced
dipoles which radiate energy away at the
same frequency as the driving wave.
(2008-01-24)
Index of refraction of water
Different colors travel at different speeds in water.
For visible light in water, the index of refraction (n) goes from
1.331 for red light to about
1.343 for violet light.
More precise data is tabulated below.
Absolute Index of Refraction of Water (n)
| n (20°C) | l
(vacuum) | Fraunhofer Line |
 |
| 1.3312 | 656.281 nm | C
( Ha ) |
Red |
| | 627.661 nm | a
( O2 ) | Orange |
| 1.3330 | 589.3 nm | D
( Na ) |
Yellow |
| | 527.039 nm | E
( Fe ) |
Green |
| 1.3372 | 486.134 nm | F
( Hb ) |
Blue |
| 1.3404 | 434.047 nm | G'
( Hg ) |
Indigo |
| 1.3435 | 396.847 nm | H
( Ca+ ) |
Violet |
 |
Data gleaned for the relative index of water with respect to either air or vacuum:
- Sodium light
(yellow, 589.3 nm) in water at t °C
(accuracy 0.00002):
nvacuum
= 1.33401 -
10-7 (66 t + 26.2 t2 - 0.1817 t3 + 0.000755 t4 )
Index of Refraction of Water
(2008-01-24)
Reflection by a raindrop
Several types of reflections are possible.
Let n be the index of refraction of the water inside a
spherical raindrop
(relative to the surrounding air).
The dominant mode of reflection is pictured at right.
Elementary geometry gives the angle q
between the incident and emergent rays as a function of the angles of
incidence (i) and refraction (r) which the rays make
with the [centripetal] normal lines at each of the three relevant
diopters:
q = 4 r
- 2 i
As i increases (starting from 0) so does
q, until a maximum is reached
where the relation 2 dr = di makes
dq vanish.
At that point, Snell's law
and its derivative translate into two simultaneous equations:
n sin r = sin i
n cos r = 2 cos i
Putting sin i = x , we have sin r = x/n.
Squaring the second relation gives:
n 2 ( 1 - x 2 / n 2 ) =
4 ( 1 - x 2 )
Therefore, x 2 = (4-n 2 ) / 3 .
Using cos 2i = 1-2x 2 we obtain:
i = ½ arccos (2n2/3 - 5/3)
Similarly, cos 2r = 1-2x2 / n2
gives
r = ½ arccos (5/3 - 8/3n2 ) . So:
|
qmax =
2 arccos (5/3 - 8/3n2 ) -
arccos (2n2/3 - 5/3)
|
With n = 1.3312
(red light in water at 20°C) we obtain
qmax = 42.34°.
On the other hand, n = 1.3435
(violet light) yields
qmax = 40.58°.
For graphics, we used
q = 42.4°,
i = 59.4°,
r = 40.4° (n = 1.3308).
As i is near the
Brewster angle of 53.08°, strong polarization occurs.
What the main relection mode produces is
the familiar sight of a beautiful
42° rainbow (the primary rainbow)
around the direction opposite
to the Sun, as explained in the next article.
(2008-01-27)
Primary and Secondary Rainbows
The spectacular show put on by water droplets.
(2008-01-27)
The 22° Halo
From ice crystals in high-altitude cirrus clouds.
Under the same conditions, an halo also exists around the Sun but it's much
harder to detect because of the blinding effect of direct sunlight.