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Metals and Non-Metals - Part X |
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Conversion
of ore into metal oxide i)
Calcination : Carbonate
ores are heated in absence of air. The absence of air and heat converts the
CO3 into CO2 and O. The O remains with the metal as
metal-oxide. Heating also expels any water content in the ore. In case these
are any volatile impurities or gases trapped in the ore, they are also removed by
heating. Calcination
can be done for ores containing carbonates. ii)
Roasting : Sulphide ores are roasted or heated in plenty of air. The
sulphide S changes to sulphur dioxide. The metal reacts with oxygen in the
air to become a metal-oxide. Heating removes gaseous and other volatile
impurities. Other
types of ores, namely metal-oxide ores and metal-chloride ores remain
unaffected by calcination and roasting processes. On treating with heat,
impurities and water are removed from these ores. Reduction
of metal-oxide i)
Reduction by heat : Metals that are unreactive, like Hg, can be
reduced from their ores by heating them. Mercury ore cinnabar is actually mercury sulphide. This can be heated
at 300°C
so that S is removed as SO2 and HgO is obtained. Hg is a very
unreactive metal. HgO dissociates into Hg and oxygen soon. The reaction is shown below. It
is interesting to note that for the cinnabar ore, roasting and reduction
processes go on one after another. ii)
Chemical reduction : Various reducing agents are used for different
metal-oxides to obtain free metals. Carbon, Al, Na, Ca are some reducing
agents that are put in use. 1) Reduction by carbon : Oxides of Zn, Fe, Ni, Sn, Pb are reduced by heating them with carbon. Metal-oxide is mixed with coke, a source of carbon, and heated in a furnace. Carbon reacts with oxygen and free metal is obtained. Example below shows how Zn is obtained from ZnO on reduction with coke. Reduction
by carbon cannot be done for more reactive metals like Mn, Al, Cr, etc.
Cu-oxide can be reduced by coke, but Ca-oxide cannot be reduced by coke. 2) Reduction by Al : This process is called as the Thermite process. Al is more reactive than carbon. Some metal-oxides that cannot be reduced by coke are reduced by Al. Al itself attracts oxygen from the metal-oxide and becomes aluminium oxide, and this frees the metal. Mn and Cr metals oxides are extracted and reduced by Al. Example below shows what happens when manganese dioxide is heated with aluminium powder. 3) Reduction by electrolysis : Highly reactive metal-oxides and metal-chlorides are not easy to be reduced by chemical reactions. Metals such as Na, K, Mn, Ca have to be freed from their ores by electrolytic processes. These metals are so reactive that they themselves are powerful reducing agents. Molten metal-oxides or chlorides form the electrolyte in the electrolytic cell. The cathode of the cell provides the electrons needed for the metal to free itself from the metal-oxide or metal-chloride bonds. Al2O3
is reduced at the cathode of an electrolytic cell as shown below. Al2O3
is melted and forms the electrolyte. Free Al++ ions are attracted
to the negatively charged cathode. Al++ is reduced by supply of
electrons at the cathode. Chlorides
of metals like Na, Mg are melted to form electrolytes. The reactions are
shown below. Chlorine
gas is liberated at the anode. The electrolysis has be done with molten
metal ores and not aqueous solutions because these metals are highly
reactive and will react with water to give hydroxides and not pure metals. In the electrolysis, metals atoms get deposited on the cathode
electrodes which then have to carefully removed and stored.
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