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Electrolysis - Part III |
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4.
Definition of standard solutions There are two types of standard solutions
Molar
Solution (M) Thus 1 M = 1 gMW of solute per litre of solution. For example, how much sodium chloride is needed to make 1 litre of a 1 M solution? First, we find out the molecular weight (MW) of sodium chloride. This is calculated as follows : The
atomic weight of sodium (Na) is 23. So
the molecular weight of sodium chloride (NaCl) is: Therefore, a 1 M solution of sodium chloride contains 58.5 grams of sodium chloride in 1 litre of solution. Similarly, a 2M solution contains 117 grams of sodium chloride per litre. And a 0.1M solution contains 5.85 grams/litre of sodium. Normal
Solution (N) To understand valency, consider the following acids: Hydrochloric acid (HCl) has one replaceable hydrogen ion (H), sulphuric acid (H2SO4) has two replaceable hydrogen ions (H2) and phosphoric acid (H3PO4) has three replaceable hydrogen ions (H3). The valencies of these acids are determined by their respective replaceable hydrogen ions: HCl,
Valency = 1 So, for 1N HCl the MW is 36.5, the EW is 36.5 and therefore 1N would correspond to 36.5 grams/litre. In case of HCL 1M solution is same as 1N solution. For 1N H2SO4 the MW is 98, the EW is 98/2 = 49 (that is, valency = 2) and so a 1 N solution would be 49 grams/litre. Similarly,
for 1N H3PO4 the MW is 98, the EW is 98/3 = 32.7 and
1N would be 32.7 grams/litre. Sodium Hydroxide (NaOH) has one replaceable hydrogen ion (OH), calcium hydroxide (Ca(OH)2) has two replaceable hydrogen ions ((OH) 2) The valencies of these acids are determined by their respective replaceable hydrogen ions: NaOH, Valency = 1 For 1N Ca(OH)2 the MW is 74, the EW is 74/2 = 37 (that is, valency = 2) and so a 1 N solution would be 37 grams/litre. Since normal solutions are a bit confusing, these days the practice is to quote strength of solutions in molar terms. 5.
Faraday’s Law of Electrolysis Thus
if m = mass of the substance released at the electrode And
Q = amount of electric charge that is passed through the electrode Then
according to Faraday’s Law of Electrolysis m If
I is the current in amperes then Q = I x t (t = time duration in seconds) Thus
m M
= Z x It Thus the electromechanical equivalent Z of a substance is defined as the amount of substance in grams liberated at any electrode when one coulomb charge is passed through an electrolyte. |
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