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Chemical Reactions - Part III |
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3.
Energy
changes in a chemical reaction
1kJ = 1000joules There are two basic type of reactions, when energy changes are considered. They are exothermic reactions and endothermic reactions. Exothermic reactions release energy as the reaction proceeds. For endothermic reactions, the energy has to be supplied to make the reaction possible. Thus, exothermic reactions will occur spontaneously when the reaction substances are brought close together. In case of endothermic reactions, the spontaneity is not present as heat has to be supplied. Examples given below will make these concepts clear. It has to be noted here that heat changes in reactions are generally available in standard books and tables; these are internationally accepted and used. Examples of exothermic reactions : 1. H
+ H When
two H mole atoms come together to form a H2
molecule
(1mole of molecule), 435.8kJ per mole of energy is released. 2.
C + H2
When
1 mole of C and 1 mole of H2
interact, they produce 1 mole of CO2
molecule and give off 395 kJ of energy. This equation shows what
happens when coal (carbon) burns in air, coal gives off energy as heat. It
is because of this reaction, coal is used as a heating substances in many
instances. Examples of endothermic reactions :
1.
N2
+
O2
+
heat If 1 mole of N2 molecule reacts with 1 mole of
O2 molecule then heat
of 184 kJ has to be supplied to initiate the reaction to give 1 mole of NO
molecule. This means that the
bonds between N
2.
CaCO3
+ heat The amount of heat given out or absorbed in a chemical reaction is called the heat of reaction. There is another definition that comes into use while discussing chemical reactions. This is heat of formation. The heat of formation is a little different from of heat of reaction. Heat of formation comes into picture when the basic compounds or molecules are forming. The amount of heat given out or absorbed when one mole of the constituent atoms is reacting to form 1 mole of the molecule, is called the heat of formation. The following examples will show how to calculate heat of formation of a compound. 1. Let us calculate the heat of formation for H2O The reaction involved is
: 2H2
+
O2 2 moles of hydrogen molecule is interacting with 1 mole of oxygen molecule to give 2 moles of water molecule Two
H The bond energy of the O If
we put in all the energies of bond formation in the equation above, we will
see that the left hand side of the equation adds up to 1365.8 kJ. The right
hand side of the equation comes to be 924.4 kJ. The heat released for making
2 moles of H2O molecule is 483 kJ. Thus for making 1 mole of H2O
molecule, 241.5 kJ/mole is released. This is the heat of formation of
water molecule. 2. Let us calculate the heat of formation for NaCl. The
reaction involved is : 2Na +
Cl2
Bond
energies involved are Na Na
Besides
bond breaking, Na atoms will also give off their excess electron. The energy
absorbed for ionization of Na to Na+ = 493.3 kJ/mole. Similarly
the energy released by Cl atoms to become Cl- negative ions
is equal to 348.2 kJ/mole. Thus
the energy consideration on the left hand side of the equation for bond
breaking and ionizing processes is 2
x 109 +
239 + 2 x 493.3 - 2 x
348.2 =
747.2 kJ The
right side of the equation has energy 2 x 769.1 = 1538.2 kJ Thus
the heat of formation of NaCl is 395.5 kJ/mole. Another
term used for indicating heat involved in a chemical reaction is the heat of
combustion. The heat released on completely burning 1 mole of a compound or
substance in air (or oxygen) is
known as the heat of combustion
of the compound or substance. If the heat of combustion is high, the
compound or the substance is a good material for burning. For example coal
is a good substance for burning because of the following reaction : [1] Einstein’s famous equation E = mc2, the missing mass becomes the binding energy of the compound or the molecule. |
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