Fractal of the Day
by Jim Muth

Chrysanthemums ©
Jim Muth's fractal image in GIF format (640x480).


Classic FOTD -- June 09, 2001   (Rating 4)

Fractal visionaries and enthusiasts:

The run of exceptional fractals had to eventually come to an end.

Due to another busy day, today's image is not only late, but it rates only a slightly below average 4.   The scene is one of a midget in the Z^1.741101127 Mandeloid, lying 11 rotations up (or is it down?) the logarithmic spiral.   The exponent is not random however.   I intentionally chose the 5th root of 16, just to see what would happen.

What happened is today's area of interesting chaos, featuring a large but harmless chrysanthemum, which is infested by a spiral and surrounded by countless smaller mums.

I doubt that the image is worth the 25 minutes it takes to draw it from the attached parameter file.   A trip to:
http://home.att.net/~Paul.N.Lee/FotD/FotD.html
or to:
http://sdboyd.dyndns.org/~sdboyd/fotd/
to download the image is recommended.

The fractal weather today was uneventful, with lots of sun and a temperature of 81F (27C).   The cats enjoy uneventful weather, so they were happy.

It's now already 10:20am of Saturday morning, and I've got chores to do around Fractal Central.   Until next time, take care, and what is the meaning of fractals?


Jim Muth
jamth@mindspring.com


START 20.0 PAR-FORMULA FILE================================

Chrysanthemums     { ; time=0:25:47.03--SF5 on a P200
  reset=2001 type=formula formulafile=allinone.frm
  formulaname=MandelbrotBC1 function=floor passes=1
  center-mag=-0.010176721962093/-0.348637919700844/2\
  682929/1/57.499 params=1.741101127/0/11/0 float=y
  maxiter=10000 inside=0 logmap=-686 periodicity=10
  colors=000FA0HD0IE0IF0JI0KJ0MK0MM0SK2ZJ2eI3kH3qF3n\
  J8kMDiOHfSKcVOaYUZaYXcaUfeRjiOmnMorJsvHvzEyzFvzFsz\
  HqyHnvHkuIjsIgqIeoJbnJ_kJZjKXiKUfMReMOcMMaNK_RIZNF\
  XO0POAUO8SZKUiXVsgXzrYzn_zkazibzfczcezafzZgzXizUjz\
  RkzOmzMnzGozYqzcrzmszmuzhvzcwzZyzUzzPvzKsyFoyAmwDi\
  wFfvIcvK_uNYuQUsSRsVOrYKr_IqbEqeBog8oj4nm2no0mr0mu\
  0nr0oo0om0qj3rg6re8sbBuaEuZHvXJwUMwROyORzMUzKXvMVr\
  NVoNVkOVgOVeQVaQVZRVVSVRSVOUVKUVHVVEVVAXV7XVBYSFZR\
  J_QNaORbNVbMZcKbeJffIjgHniFriEvjDzkBzmAzn8zn7oc3VV\
  0AK00B00I07O0FV0N_0Vf0bm3jr4ry7zz8zzAzz7zz4zz2zz0z\
  z0zz0zz0zy0zu0zr0yn0vk0ug0re0qa0nZ0mV0jS0iO0gM0ZaE\
  RqUJzgKzeMzcMzbNyaNw_OvZOuYQrXQqVRoURnSSmRSkQUjOUi\
  NSeJSaHSZESVARS7RO4RM0RI0RF0UI0XK4YMA_OEbRIcSNfVRi\
  YVjZ_macocgqemsgqvjuwkzznzzozzqzzrzzswzusyvoywmyyi\
  yzfwzbwzZwzXwzSvzOvzMvzIvzFwzIwzKwzNwzOwzRwzUwzVwz\
  Ywz_wzbwzcwzfyziyzjyzmyzo
  }

frm:MandelbrotBC1   { ; by several Fractint users
  e=p1, a=imag(p2)+100
  p=real(p2)+PI
  q=2*PI*fn1(p/(2*PI))
  r=real(p2)-q
  Z=C=Pixel:
    Z=log(Z)
    IF(imag(Z) > r)
      Z=Z+flip(2*PI)
    ENDIF
    Z=exp(e*(Z+flip(q)))+C
  |Z| < a  }

END 20.0 PAR-FORMULA FILE==================================


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